Given n, generate all structurally unique BST's (binary search trees) that store values 1...n.
For example,
Given n = 3, your program should return all 5 unique BST's shown below.
Given n = 3, your program should return all 5 unique BST's shown below.
1 3 3 2 1
\ / / / \ \
3 2 1 1 3 2
/ / \ \
2 1 2 3
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<TreeNode *> generateTrees(int n) {
vector<TreeNode*> res;
help(1,n,res);
return res;
}
void help(int first,int last,vector<TreeNode*>& res)
{
if (first>last)
{
res.push_back(NULL);
return;
}
for (int i=first;i<=last;i++)
{
vector<TreeNode*> leftChild,rightChild;
help(first,i-1,leftChild);
help(i+1,last,rightChild);
for (int j=0;j<leftChild.size();j++)
{
for (int k=0;k<rightChild.size();k++)
{
TreeNode* root = new TreeNode(i);
root->left = leftChild[j];
root->right = rightChild[k];
res.push_back(root);
}
}
}
}
};
No comments:
Post a Comment