Implement regular expression matching with support for
'.' and '*'.'.' Matches any single character.
'*' Matches zero or more of the preceding element.
The matching should cover the entire input string (not partial).
The function prototype should be:
bool isMatch(const char *s, const char *p)
Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "a*") → true
isMatch("aa", ".*") → true
isMatch("ab", ".*") → true
isMatch("aab", "c*a*b") → true
class Solution {
public:
bool isMatch(const char *s, const char *p) {
if (*s=='\0')
{
while(strlen(p)>=2 && *(p+1)=='*')
p+=2;
return *p=='\0';
}
if (*p=='\0')
{
return *s=='\0';
}
if (strlen(p)==1)
return (strlen(s)==1) && (*s==*p || *p=='.');
if (*(p+1)!='*')
{
if (*s==*p || *p=='.')
return isMatch(s+1,p+1);
return false;
}
else
{
if (isMatch(s,p+2))
return true;
if (*s==*p || *p=='.')
return isMatch(s+1,p);
return false;
}
}
};
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