Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
For example,
Given the following matrix:
Given the following matrix:
[ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ]
You should return
[1,2,3,6,9,8,7,4,5].class Solution {
public:
vector<int> spiralOrder(vector<vector<int> > &matrix) {
vector<int> res;
int m= matrix.size();
if (m<=0)
return res;
int n = matrix[0].size();
if (n<=0)
return res;
int left = 0,right = n-1;
int up=0,down=m-1;
while(left<=right && up<=down)
{
for (int j=left;j<=right;j++)
{
res.push_back(matrix[up][j]);
}
up++;
for (int i=up;i<=down;i++)
{
res.push_back(matrix[i][right]);
}
right--;
if (up<=down)
{
for (int j=right;j>=left;j--)
{
res.push_back(matrix[down][j]);
}
}
down--;
if (left<=right)
{
for (int i=down;i>=up;i--)
{
res.push_back(matrix[i][left]);
}
}
left++;
}
return res;
}
};
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