You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Solution: step[n]=step[n-1]+step[n-2], Fibonacci sequence Dynamic programming or iterations
class Solution {
public:
int climbStairs(int n) {
if (n<=1)
return n;
if (n==2)
return 2;
int first = 1;
int second = 2;
int res = 0;
for (int i=3;i<=n;i++)
{
res = first+second;
first = second;
second = res;
}
return res;
}
};
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