Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the
The
For instance,
. character.The
. character does not represent a decimal point and is used to separate number sequences.For instance,
2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
class Solution {
public:
int compareVersion(string version1, string version2) {
int pos1=0;
int pos2=0;
int token1=getToken(version1,pos1);
int token2=getToken(version2,pos2);
while((pos1<version1.size() || pos2<version2.size()) && token1==token2)
{
token1=getToken(version1,pos1);
token2=getToken(version2,pos2);
}
if (token1==token2)
return 0;
if (token1>token2)
return 1;
return -1;
}
int getToken(string &version,int &pos)
{
if (pos>=version.size())
return 0;
int res=0;
while(pos<version.size() && version[pos]!='.')
{
res = res*10+version[pos]-'0';
pos++;
}
if (version[pos]=='.')
pos++;
return res;
}
};
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