Given a string s consists of upper/lower-case alphabets and empty space characters
' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s =
return
Given s =
"Hello World",return
5.class Solution {
public:
int lengthOfLastWord(const char *s) {
if (strlen(s)<=0)
return 0;
int pos = strlen(s)-1;
int count=0;
for (;pos>=0;pos--)
{
if (s[pos]==' ')
{
if (count==0)
continue;
return count;
}
else
{
count++;
}
}
return count;
}
};
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